What is the general solution for tan(θ)=-(sqrt(3))/1 ?

The general solution for tan(θ)=-(sqrt(3))/1 is θ=(2pi)/3+pin

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tan(θ)=-(sqrt(3))/1

tan (θ) = - \frac{3}{1}

θ = \frac{2 π}{3} + πn

Degrees

θ = 12 0^{\circ} + 18 0^{\circ} n

Solution steps

tan (θ) = - \frac{3}{1}

Apply rule

\frac{a}{1} = a

tan (θ) = - 3

General solutions for

tan (θ) = - 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

θ = \frac{2 π}{3} + πn

θ = \frac{2 π}{3} + πn

sin (3 x) + cos (3 x) = 0

sin (x) = - \frac{3}{4}, π < x < \frac{3 π}{4}

cos (2 x) + cos (x) = 0, 0 \leq x < 2 π

10 cos^{2} (x) = 5

cos (θ) = \frac{5}{9}

What is the general solution for tan(θ)=-(sqrt(3))/1 ?
The general solution for tan(θ)=-(sqrt(3))/1 is θ=(2pi)/3+pin