What is the general solution for tan(2x-pi/6)=-1/(sqrt(3)) ?

The general solution for tan(2x-pi/6)=-1/(sqrt(3)) is x=(pin)/2+pi/2

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tan(2x-pi/6)=-1/(sqrt(3))

tan (2 x - \frac{π}{6}) = - \frac{1}{3}

x = \frac{πn}{2} + \frac{π}{2}

Solution steps

tan (2 x - \frac{π}{6}) = - \frac{1}{3}

Simplify

- \frac{1}{3} : - \frac{3}{3}

General solutions for

tan (2 x - \frac{π}{6}) = - \frac{3}{3}

2 x - \frac{π}{6} = \frac{5 π}{6} + πn

Solve

2 x - \frac{π}{6} = \frac{5 π}{6} + πn : x = \frac{πn}{2} + \frac{π}{2}

x = \frac{πn}{2} + \frac{π}{2}

4 cos^{2} (2 x) - 2 = 0

tan (θ) = \frac{9}{12}

tan (a) = \frac{20}{21}

sin (\frac{2 x}{3}) = - 1

3 tan (θ) sin (θ) - 2 tan (θ) = 0

What is the general solution for tan(2x-pi/6)=-1/(sqrt(3)) ?
The general solution for tan(2x-pi/6)=-1/(sqrt(3)) is x=(pin)/2+pi/2