What is the general solution for sin(θ)=(-sqrt(2))/2 ?

The general solution for sin(θ)=(-sqrt(2))/2 is θ=(5pi)/4+2pin,θ=(7pi)/4+2pin

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sin(θ)=(-sqrt(2))/2

sin (θ) = \frac{- 2}{2}

θ = \frac{5 π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

sin (θ) = \frac{- 2}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

sin (θ) = - \frac{2}{2}

General solutions for

sin (θ) = - \frac{2}{2}

θ = \frac{5 π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

cos (θ) csc (θ) = - 2 cos (θ)

csc^{2} (x) - 4 cot (x) = - 2

sin (2 x - \frac{π}{3}) = \frac{3}{2}

- sin^{3} (t) + sin (2 t) cos (t) = 0

tan (θ) = 3 tan (4 5^{\circ})

What is the general solution for sin(θ)=(-sqrt(2))/2 ?
The general solution for sin(θ)=(-sqrt(2))/2 is θ=(5pi)/4+2pin,θ=(7pi)/4+2pin