What is the general solution for sin(u)=1 ?

The general solution for sin(u)=1 is u= pi/2+2pin

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sin(u)=1

sin (u) = 1

u = \frac{π}{2} + 2 πn

Degrees

u = 9 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (u) = 1

General solutions for

sin (u) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

u = \frac{π}{2} + 2 πn

u = \frac{π}{2} + 2 πn

tan (x) - 1 = \frac{1}{3} - \frac{1}{3} cot (x)

22 cos (x) + 3 = 5

4 tan^{2} (x) + 14 tan (x) + 12 = 0

13 (1 - cos (θ)) = sin^{2} (θ)

8 arcsin (x) = 2 π

What is the general solution for sin(u)=1 ?
The general solution for sin(u)=1 is u= pi/2+2pin