What is the general solution for 2sin(1/2 x)+1=0 ?

The general solution for 2sin(1/2 x)+1=0 is x=(7pi)/3+4pin,x=(11pi)/3+4pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2sin(1/2 x)+1=0

2 sin (\frac{1}{2} x) + 1 = 0

x = \frac{7 π}{3} + 4 πn, x = \frac{11 π}{3} + 4 πn

Solution steps

2 sin (\frac{1}{2} x) + 1 = 0

Move

1

to the right side

2 sin (\frac{1}{2} x) = - 1

Divide both sides by

2

sin (\frac{1}{2} x) = - \frac{1}{2}

General solutions for

sin (\frac{1}{2} x) = - \frac{1}{2}

\frac{1}{2} x = \frac{7 π}{6} + 2 πn, \frac{1}{2} x = \frac{11 π}{6} + 2 πn

Solve

\frac{1}{2} x = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{3} + 4 πn

Solve

\frac{1}{2} x = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{3} + 4 πn

x = \frac{7 π}{3} + 4 πn, x = \frac{11 π}{3} + 4 πn

sin (x) = - \frac{5}{2}

csc (x) = - \frac{7}{6}, tan (x) > 0

tan^{2} (x) + 4 sec (x) + 5 = 0

tan^{2} (θ) - 6 sec (θ) = 6

cos^{2} (x) - sin^{2} (x) - sin (x) = 0

What is the general solution for 2sin(1/2 x)+1=0 ?
The general solution for 2sin(1/2 x)+1=0 is x=(7pi)/3+4pin,x=(11pi)/3+4pin