What is the general solution for sin(θ-pi/3)+1=0 ?

The general solution for sin(θ-pi/3)+1=0 is θ=2pin+(11pi)/6

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sin(θ-pi/3)+1=0

sin (θ - \frac{π}{3}) + 1 = 0

θ = 2 πn + \frac{11 π}{6}

Solution steps

sin (θ - \frac{π}{3}) + 1 = 0

Move

1

to the right side

sin (θ - \frac{π}{3}) = - 1

General solutions for

sin (θ - \frac{π}{3}) = - 1

θ - \frac{π}{3} = \frac{3 π}{2} + 2 πn

Solve

θ - \frac{π}{3} = \frac{3 π}{2} + 2 πn : θ = 2 πn + \frac{11 π}{6}

θ = 2 πn + \frac{11 π}{6}

tan^{2} (2 θ) = tan (2 θ)

2 cos (2 x) = 2 sin (x)

- sin (θ) + 1 + cos (θ) = 0

sin (x) = \frac{1}{10}

θ, sin (θ) = 0

What is the general solution for sin(θ-pi/3)+1=0 ?
The general solution for sin(θ-pi/3)+1=0 is θ=2pin+(11pi)/6