What is the general solution for -2cos(B)+4=cos(B)+6 ?

The general solution for -2cos(B)+4=cos(B)+6 is B=2.30052…+2pin,B=-2.30052…+2pin

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-2cos(B)+4=cos(B)+6

- 2 cos (B) + 4 = cos (B) + 6

B = 2.30052 \dots + 2 πn, B = - 2.30052 \dots + 2 πn

Solution steps

- 2 cos (B) + 4 = cos (B) + 6

Solve by substitution

cos (B) = - \frac{2}{3}

cos (B) = - \frac{2}{3} : B = arccos (- \frac{2}{3}) + 2 πn, B = - arccos (- \frac{2}{3}) + 2 πn

Combine all the solutions

B = arccos (- \frac{2}{3}) + 2 πn, B = - arccos (- \frac{2}{3}) + 2 πn

Show solutions in decimal form

B = 2.30052 \dots + 2 πn, B = - 2.30052 \dots + 2 πn

4 - 2 sin^{2} (x) = - sin (x) + 3

csc^{3} (x) + csc^{2} (x) = 2 csc (x) + 2

cot^{2} (x) sin (x) = cot^{2} (x)

2 cos^{2} (w) + cos (w) - 3 = 0

csc (2 x) = \frac{3}{2}

What is the general solution for -2cos(B)+4=cos(B)+6 ?
The general solution for -2cos(B)+4=cos(B)+6 is B=2.30052…+2pin,B=-2.30052…+2pin