What is the general solution for -2sin(B)-6=sin(B)-3 ?

The general solution for -2sin(B)-6=sin(B)-3 is B=(3pi)/2+2pin

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-2sin(B)-6=sin(B)-3

- 2 sin (B) - 6 = sin (B) - 3

B = \frac{3 π}{2} + 2 πn

Solution steps

- 2 sin (B) - 6 = sin (B) - 3

Solve by substitution

sin (B) = - 1

sin (B) = - 1 : B = \frac{3 π}{2} + 2 πn

Combine all the solutions

B = \frac{3 π}{2} + 2 πn

sin (x) (2 sin (x) + 1) = 2

4 sin (θ) + 1 = 0

sin^{2} (θ) (1 + csc^{2} (θ)) = k

- 3 cos (2 θ) + 9 cos (θ) - 7 = 4 cos (θ) - 3

sin (4 0^{\circ} - x) = cos (3 x)

What is the general solution for -2sin(B)-6=sin(B)-3 ?
The general solution for -2sin(B)-6=sin(B)-3 is B=(3pi)/2+2pin