What is the general solution for 0=-4cos(3x)+2sqrt(2) ?

The general solution for 0=-4cos(3x)+2sqrt(2) is x= pi/(12)+(2pin)/3 ,x=(7pi}{12}+\frac{2pin)/3

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0=-4cos(3x)+2sqrt(2)

0 = - 4 cos (3 x) + 22

x = \frac{π}{12} + \frac{2 πn}{3}, x = \frac{7 π}{12} + \frac{2 πn}{3}

Solution steps

0 = - 4 cos (3 x) + 22

Switch sides

- 4 cos (3 x) + 22 = 0

Move

22

to the right side

- 4 cos (3 x) = - 22

Divide both sides by

- 4

cos (3 x) = \frac{2}{2}

General solutions for

cos (3 x) = \frac{2}{2}

3 x = \frac{π}{4} + 2 πn, 3 x = \frac{7 π}{4} + 2 πn

Solve

3 x = \frac{π}{4} + 2 πn : x = \frac{π}{12} + \frac{2 πn}{3}

Solve

3 x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{12} + \frac{2 πn}{3}

x = \frac{π}{12} + \frac{2 πn}{3}, x = \frac{7 π}{12} + \frac{2 πn}{3}

6 sin (x) = 0

2 sin^{2} (θ) + cos (θ) = 0, 0 \leq θ \leq 2 π

cos (a) - 1 = 2 cos (a)

3 cos^{2} (θ) - sin (θ) = 1

5 cos (2 x) = 9 sin (x) + 4

What is the general solution for 0=-4cos(3x)+2sqrt(2) ?
The general solution for 0=-4cos(3x)+2sqrt(2) is x= pi/(12)+(2pin)/3 ,x=(7pi}{12}+\frac{2pin)/3