What is the general solution for cos(2x)*2-1=0 ?

The general solution for cos(2x)*2-1=0 is x= pi/6+pin,x=(5pi)/6+pin

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cos(2x)*2-1=0

cos (2 x) \cdot 2 - 1 = 0

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

Solution steps

cos (2 x) \cdot 2 - 1 = 0

Move

1

to the right side

cos (2 x) \cdot 2 = 1

Divide both sides by

2

cos (2 x) = \frac{1}{2}

General solutions for

cos (2 x) = \frac{1}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{5 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{5 π}{3} + 2 πn : x = \frac{5 π}{6} + πn

x = \frac{π}{6} + πn, x = \frac{5 π}{6} + πn

sec^{2} (x) + sec (x) - 6 = 0

4 + 3 sin (θ) = 0

sin (θ) sec (θ) = cos (θ) csc (θ)

∣ cos (x) ∣ = \frac{1}{a}

sin (a) = \frac{1}{3}

What is the general solution for cos(2x)*2-1=0 ?
The general solution for cos(2x)*2-1=0 is x= pi/6+pin,x=(5pi)/6+pin