What is the general solution for cos(θ)(cos(θ)-2)=1,-180<= θ<= 180 ?

The general solution for cos(θ)(cos(θ)-2)=1,-180<= θ<= 180 is θ=1.99787…,θ=-1.99787…

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cos(θ)(cos(θ)-2)=1,-180<= θ<= 180

cos (θ) (cos (θ) - 2) = 1, - 18 0^{\circ} \leq θ \leq 18 0^{\circ}

θ = 1.99787 \dots, θ = - 1.99787 \dots

Solution steps

cos (θ) (cos (θ) - 2) = 1, - 18 0^{\circ} \leq θ \leq 18 0^{\circ}

Solve by substitution

cos (θ) = 1 + 2, cos (θ) = 1 - 2

cos (θ) = 1 + 2, - 18 0^{\circ} \leq θ \leq 18 0^{\circ} :

No Solution

cos (θ) = 1 - 2, - 18 0^{\circ} \leq θ \leq 18 0^{\circ} : θ = arccos (1 - 2), θ = - arccos (1 - 2)

Combine all the solutions

θ = arccos (1 - 2), θ = - arccos (1 - 2)

Show solutions in decimal form

θ = 1.99787 \dots, θ = - 1.99787 \dots

sin (3 9^{\circ}) + sin (2 1^{\circ}) = sin (a^{\circ})

arctan (4 x - 4) = - 1

tan^{2} (x + \frac{π}{6}) = 3

cos (θ) cos (2 θ) + sin (θ) sin (2 θ) = \frac{3}{2}

3 cos (2 x) - 2 cos (x) - 1 = 0

What is the general solution for cos(θ)(cos(θ)-2)=1,-180<= θ<= 180 ?
The general solution for cos(θ)(cos(θ)-2)=1,-180<= θ<= 180 is θ=1.99787…,θ=-1.99787…