What is the general solution for 10cos(B)+6=4cos(B)+4 ?

The general solution for 10cos(B)+6=4cos(B)+4 is B=1.91063…+2pin,B=-1.91063…+2pin

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10cos(B)+6=4cos(B)+4

10 cos (B) + 6 = 4 cos (B) + 4

B = 1.91063 \dots + 2 πn, B = - 1.91063 \dots + 2 πn

Solution steps

10 cos (B) + 6 = 4 cos (B) + 4

Solve by substitution

cos (B) = - \frac{1}{3}

cos (B) = - \frac{1}{3} : B = arccos (- \frac{1}{3}) + 2 πn, B = - arccos (- \frac{1}{3}) + 2 πn

Combine all the solutions

B = arccos (- \frac{1}{3}) + 2 πn, B = - arccos (- \frac{1}{3}) + 2 πn

Show solutions in decimal form

B = 1.91063 \dots + 2 πn, B = - 1.91063 \dots + 2 πn

2 sin (x) + 2 sin (x) tan (x) = 0

y, x = x (1 + tan (y))

- 9 cos^{2} (θ) + sin (θ) + 11 = - sin (θ) + 2

sin (θ) = 1 - 2 cos (θ)

6 sec^{2} (x) - 6 sec (x) = 12

What is the general solution for 10cos(B)+6=4cos(B)+4 ?
The general solution for 10cos(B)+6=4cos(B)+4 is B=1.91063…+2pin,B=-1.91063…+2pin