What is the general solution for cos^2(x)+2sin(x)+2=0 ?

The general solution for cos^2(x)+2sin(x)+2=0 is x=(3pi)/2+2pin

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cos^2(x)+2sin(x)+2=0

cos^{2} (x) + 2 sin (x) + 2 = 0

x = \frac{3 π}{2} + 2 πn

Solution steps

cos^{2} (x) + 2 sin (x) + 2 = 0

Rewrite using trig identities

3 - sin^{2} (x) + 2 sin (x) = 0

Solve by substitution

sin (x) = - 1, sin (x) = 3

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

sin (x) = 3 :

No Solution

Combine all the solutions

x = \frac{3 π}{2} + 2 πn

2 sin^{2} (2 x + π) - sin (2 x + π) - 1 = 0

cos (x) = 9

sec (θ) = \frac{3}{5}

cos (3 x) + 2 cos (x) = 0

sin (x + \frac{π}{2}) - cos (x + \frac{3 π}{2}) = 0

What is the general solution for cos^2(x)+2sin(x)+2=0 ?
The general solution for cos^2(x)+2sin(x)+2=0 is x=(3pi)/2+2pin