What is the general solution for 3arccos(x)=2 ?

The general solution for 3arccos(x)=2 is x=cos(2/3)

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3arccos(x)=2

3 arccos (x) = 2

x = cos (\frac{2}{3})

Solution steps

3 arccos (x) = 2

Divide both sides by

3

3 arccos (x) = 2

Divide both sides by

3

\frac{3 arccos ( x )}{3} = \frac{2}{3}

Simplify

arccos (x) = \frac{2}{3}

arccos (x) = \frac{2}{3}

Apply trig inverse properties

arccos (x) = \frac{2}{3}

arccos (x) = a \Rightarrow x = cos (a)

x = cos (\frac{2}{3})

x = cos (\frac{2}{3})

cos (4 x) = - \frac{1}{2}, 0 \leq x \leq 2 π

3 csc^{2} (x) + 1.5 cot (x) = 15

sin (y) = cos (y)

\frac{cos ( x )}{sin ( x )} = 2

θ, 2 cos^{2} (θ) + 9 cos (θ) - 5 = 0

What is the general solution for 3arccos(x)=2 ?
The general solution for 3arccos(x)=2 is x=cos(2/3)