What is the general solution for -3sin(t)=0 ?

The general solution for -3sin(t)=0 is t=2pin,t=pi+2pin

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-3sin(t)=0

- 3 sin (t) = 0

t = 2 πn, t = π + 2 πn

Degrees

t = 0^{\circ} + 36 0^{\circ} n, t = 18 0^{\circ} + 36 0^{\circ} n

Solution steps

- 3 sin (t) = 0

Divide both sides by

- 3

- 3 sin (t) = 0

Divide both sides by

- 3

\frac{- 3 sin ( t )}{- 3} = \frac{0}{- 3}

Simplify

sin (t) = 0

sin (t) = 0

General solutions for

sin (t) = 0

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

t = 0 + 2 πn, t = π + 2 πn

t = 0 + 2 πn, t = π + 2 πn

Solve

t = 0 + 2 πn : t = 2 πn

t = 0 + 2 πn

0 + 2 πn = 2 πn

t = 2 πn

t = 2 πn, t = π + 2 πn

x, 0 = cos (x) - sin (x)

3 cos^{2} (θ) + 7 cos (θ) - 8 = 0

2 cos (2 a) = 2, 0 \leq θ \leq 2 π

t, y^{4} - 81 y = sin (t)

11 sin (B) - 1 = 3 sin (B) - 1

What is the general solution for -3sin(t)=0 ?
The general solution for -3sin(t)=0 is t=2pin,t=pi+2pin