What is the general solution for sin(2x-0.35)=cos(3x) ?

The general solution for sin(2x-0.35)=cos(3x) is x=(0.35+pi/2+6.28318…n)/5 ,x=-0.35-6.28318…n-pi/2

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sin(2x-0.35)=cos(3x)

sin (2 x - 0.35) = cos (3 x)

x = \frac{0.35 + \frac{π}{2} + 6.28318 \dots n}{5}, x = - 0.35 - 6.28318 \dots n - \frac{π}{2}

Solution steps

sin (2 x - 0.35) = cos (3 x)

Rewrite using trig identities

sin (2 x - 0.35) = sin (\frac{π}{2} - 3 x)

Apply trig inverse properties

2 x - 0.35 = \frac{π}{2} - 3 x + 2 πn, 2 x - 0.35 = π - (\frac{π}{2} - 3 x) + 2 πn

2 x - 0.35 = \frac{π}{2} - 3 x + 2 πn : x = \frac{0.35 + \frac{π}{2} + 6.28318 \dots n}{5}

2 x - 0.35 = π - (\frac{π}{2} - 3 x) + 2 πn : x = - 0.35 - 6.28318 \dots n - \frac{π}{2}

x = \frac{0.35 + \frac{π}{2} + 6.28318 \dots n}{5}, x = - 0.35 - 6.28318 \dots n - \frac{π}{2}

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What is the general solution for sin(2x-0.35)=cos(3x) ?
The general solution for sin(2x-0.35)=cos(3x) is x=(0.35+pi/2+6.28318…n)/5 ,x=-0.35-6.28318…n-pi/2