What is the general solution for sin^2(x)-cos^2(x)=0,(0,2pi) ?

The general solution for sin^2(x)-cos^2(x)=0,(0,2pi) is x= pi/4 ,x=(3pi)/4 ,x=(5pi)/4 ,x=(7pi)/4

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sin^2(x)-cos^2(x)=0,(0,2pi)

sin^{2} (x) - cos^{2} (x) = 0, (0, 2 π)

x = \frac{π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}, x = \frac{7 π}{4}

Solution steps

sin^{2} (x) - cos^{2} (x) = 0, (0, 2 π)

Rewrite using trig identities

- cos (2 x) = 0

Divide both sides by

- 1

cos (2 x) = 0

General solutions for

cos (2 x) = 0

2 x = \frac{π}{2} + 2 πn, 2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{π}{2} + 2 πn : x = \frac{π}{4} + πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{π}{4} + πn, x = \frac{3 π}{4} + πn

Solutions for the range

(0, 2 π)

x = \frac{π}{4}, x = \frac{3 π}{4}, x = \frac{5 π}{4}, x = \frac{7 π}{4}

tan (α) = - 0.9857

8 sin^{2} (x) = 8 - 4 cos (x)

sec^{2} (θ) = 9

cos (x) = \frac{6.5}{8.4}

tan (θ) = \frac{1}{10}

What is the general solution for sin^2(x)-cos^2(x)=0,(0,2pi) ?
The general solution for sin^2(x)-cos^2(x)=0,(0,2pi) is x= pi/4 ,x=(3pi)/4 ,x=(5pi)/4 ,x=(7pi)/4