What is the general solution for 2cos(t)=1,-pi<= t<= pi ?

The general solution for 2cos(t)=1,-pi<= t<= pi is t= pi/3 ,t=-pi/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2cos(t)=1,-pi<= t<= pi

2 cos (t) = 1, - π \leq t \leq π

t = \frac{π}{3}, t = - \frac{π}{3}

Solution steps

2 cos (t) = 1, - π \leq t \leq π

Divide both sides by

2

cos (t) = \frac{1}{2}

General solutions for

cos (t) = \frac{1}{2}

t = \frac{π}{3} + 2 πn, t = \frac{5 π}{3} + 2 πn

Solutions for the range

- π \leq t \leq π

t = \frac{π}{3}, t = - \frac{π}{3}

tan (\frac{x}{3}) = 1, 0 \leq x \leq 2 π

4 sin (x) = sin (x) tan (x)

cos (x) = 0.707

4 cos^{2} (x) - 4 cos (x) - 3 = 0

cot (x) = \frac{4}{3}

What is the general solution for 2cos(t)=1,-pi<= t<= pi ?
The general solution for 2cos(t)=1,-pi<= t<= pi is t= pi/3 ,t=-pi/3