What is the general solution for tan^2(θ)+2tan(θ)=-1 ?

The general solution for tan^2(θ)+2tan(θ)=-1 is θ=(3pi)/4+pin

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tan^2(θ)+2tan(θ)=-1

tan^{2} (θ) + 2 tan (θ) = - 1

θ = \frac{3 π}{4} + πn

Solution steps

tan^{2} (θ) + 2 tan (θ) = - 1

Solve by substitution

tan (θ) = - 1

tan (θ) = - 1 : θ = \frac{3 π}{4} + πn

Combine all the solutions

θ = \frac{3 π}{4} + πn

cos (a) = \frac{2}{3}

- 1 = cos (π t)

2 tan^{2} (θ) = 6

cos^{2} (θ + \frac{π}{6}) = \frac{1}{2}

2 sin (2 x) = 2 sin (x)

What is the general solution for tan^2(θ)+2tan(θ)=-1 ?
The general solution for tan^2(θ)+2tan(θ)=-1 is θ=(3pi)/4+pin