What is the general solution for 2sin(x+1.2)-4.22=-4 ?

The general solution for 2sin(x+1.2)-4.22=-4 is x=0.11022…+2pin-1.2,x=pi-0.11022…+2pin-1.2

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2sin(x+1.2)-4.22=-4

2 sin (x + 1.2) - 4.22 = - 4

x = 0.11022 \dots + 2 πn - 1.2, x = π - 0.11022 \dots + 2 πn - 1.2

Solution steps

2 sin (x + 1.2) - 4.22 = - 4

Move

4.22

to the right side

2 sin (x + 1.2) = 0.22

Divide both sides by

2

sin (x + 1.2) = 0.11

Apply trig inverse properties

x + 1.2 = arcsin (0.11) + 2 πn, x + 1.2 = π - arcsin (0.11) + 2 πn

Solve

x + 1.2 = arcsin (0.11) + 2 πn : x = arcsin (0.11) + 2 πn - 1.2

Solve

x + 1.2 = π - arcsin (0.11) + 2 πn : x = π - arcsin (0.11) + 2 πn - 1.2

x = arcsin (0.11) + 2 πn - 1.2, x = π - arcsin (0.11) + 2 πn - 1.2

Show solutions in decimal form

x = 0.11022 \dots + 2 πn - 1.2, x = π - 0.11022 \dots + 2 πn - 1.2

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6 sin^{2} (θ) - 5 sin (θ) = - 1

csc (x) = - 4

What is the general solution for 2sin(x+1.2)-4.22=-4 ?
The general solution for 2sin(x+1.2)-4.22=-4 is x=0.11022…+2pin-1.2,x=pi-0.11022…+2pin-1.2