What is the general solution for 5cos^2(θ)=-13cos(θ)+6 ?

The general solution for 5cos^2(θ)=-13cos(θ)+6 is θ=1.15927…+2pin,θ=2pi-1.15927…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5cos^2(θ)=-13cos(θ)+6

5 cos^{2} (θ) = - 13 cos (θ) + 6

θ = 1.15927 \dots + 2 πn, θ = 2 π - 1.15927 \dots + 2 πn

Solution steps

5 cos^{2} (θ) = - 13 cos (θ) + 6

Solve by substitution

cos (θ) = \frac{2}{5}, cos (θ) = - 3

cos (θ) = \frac{2}{5} : θ = arccos (\frac{2}{5}) + 2 πn, θ = 2 π - arccos (\frac{2}{5}) + 2 πn

cos (θ) = - 3 :

No Solution

Combine all the solutions

θ = arccos (\frac{2}{5}) + 2 πn, θ = 2 π - arccos (\frac{2}{5}) + 2 πn

Show solutions in decimal form

θ = 1.15927 \dots + 2 πn, θ = 2 π - 1.15927 \dots + 2 πn

- 3 sin (x) - cos (x) = 0

tan (θ) + sec (θ) = 1

6 sin (x) + 8 = 0

2 cos (x) - 7 = 4 sec (x)

3 (cos (2 x) + \frac{3}{2}) = 6

What is the general solution for 5cos^2(θ)=-13cos(θ)+6 ?
The general solution for 5cos^2(θ)=-13cos(θ)+6 is θ=1.15927…+2pin,θ=2pi-1.15927…+2pin