What is the general solution for tan^2(x)-(sqrt(3)+1)tan(x)+sqrt(3)=0 ?

The general solution for tan^2(x)-(sqrt(3)+1)tan(x)+sqrt(3)=0 is x= pi/3+pin,x= pi/4+pin

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tan^2(x)-(sqrt(3)+1)tan(x)+sqrt(3)=0

tan^{2} (x) - (3 + 1) tan (x) + 3 = 0

x = \frac{π}{3} + πn, x = \frac{π}{4} + πn

Solution steps

tan^{2} (x) - (3 + 1) tan (x) + 3 = 0

Solve by substitution

tan (x) = 3, tan (x) = 1

tan (x) = 3 : x = \frac{π}{3} + πn

tan (x) = 1 : x = \frac{π}{4} + πn

Combine all the solutions

x = \frac{π}{3} + πn, x = \frac{π}{4} + πn

6 cos (θ) = 3

4 cos^{3} (x) = cos (x)

csc^{5} (θ) - 4 csc (θ) = 0

16 sin^{2} (x) - 4 = 0

3 - 3 sin (θ) = 3

What is the general solution for tan^2(x)-(sqrt(3)+1)tan(x)+sqrt(3)=0 ?
The general solution for tan^2(x)-(sqrt(3)+1)tan(x)+sqrt(3)=0 is x= pi/3+pin,x= pi/4+pin