What is the general solution for 6cos(A)+sqrt(18)=0 ?

The general solution for 6cos(A)+sqrt(18)=0 is A=(3pi)/4+2pin,A=(5pi)/4+2pin

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6cos(A)+sqrt(18)=0

6 cos (A) + 18 = 0

A = \frac{3 π}{4} + 2 πn, A = \frac{5 π}{4} + 2 πn

Solution steps

6 cos (A) + 18 = 0

18 = 32

6 cos (A) + 32 = 0

Move

32

to the right side

6 cos (A) = - 32

Divide both sides by

6

cos (A) = - \frac{2}{2}

General solutions for

cos (A) = - \frac{2}{2}

A = \frac{3 π}{4} + 2 πn, A = \frac{5 π}{4} + 2 πn

csc (θ) = \frac{5}{2}

sin (θ) + 3 = 5 sin (θ)

2 sin^{2} (x) - cos (2 x) = 0

csc (x) cos^{2} (x) + sin^{2} (x) = csc (x)

0.87 = 5 cos (3 x)

What is the general solution for 6cos(A)+sqrt(18)=0 ?
The general solution for 6cos(A)+sqrt(18)=0 is A=(3pi)/4+2pin,A=(5pi)/4+2pin