What is the general solution for tan(pi+c)=1 ?

The general solution for tan(pi+c)=1 is c= pi/4+pin-pi

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tan(pi+c)=1

tan (π + c) = 1

c = \frac{π}{4} + πn - π

Solution steps

tan (π + c) = 1

General solutions for

tan (π + c) = 1

π + c = \frac{π}{4} + πn

Solve

π + c = \frac{π}{4} + πn : c = \frac{π}{4} + πn - π

c = \frac{π}{4} + πn - π

8 sin^{2} (x) = 8 cos^{2} (x)

sin (x) = \frac{6}{8}

tan (x) = 2 + tan (3 x)

2 sin (x) - 3 = 0

sin^{2} (x) = 2 sin^{2} (\frac{x}{2})

What is the general solution for tan(pi+c)=1 ?
The general solution for tan(pi+c)=1 is c= pi/4+pin-pi