What is the general solution for 1-sqrt(2)cos(θ)=0 ?

The general solution for 1-sqrt(2)cos(θ)=0 is θ= pi/4+2pin,θ=(7pi)/4+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1-sqrt(2)cos(θ)=0

1 - 2 cos (θ) = 0

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Degrees

θ = 4 5^{\circ} + 36 0^{\circ} n, θ = 31 5^{\circ} + 36 0^{\circ} n

Solution steps

1 - 2 cos (θ) = 0

Move

1

to the right side

1 - 2 cos (θ) = 0

Subtract

1

from both sides

1 - 2 cos (θ) - 1 = 0 - 1

Simplify

- 2 cos (θ) = - 1

- 2 cos (θ) = - 1

Divide both sides by

- 2

- 2 cos (θ) = - 1

Divide both sides by

- 2

\frac{- 2 cos ( θ )}{- 2} = \frac{- 1}{- 2}

Simplify

\frac{- 2 cos ( θ )}{- 2} = \frac{- 1}{- 2}

Simplify

\frac{- 2 cos ( θ )}{- 2} : cos (θ)

\frac{- 2 cos ( θ )}{- 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 cos ( θ )}{2}

Cancel the common factor:

2

= cos (θ)

Simplify

\frac{- 1}{- 2} : \frac{2}{2}

\frac{- 1}{- 2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{1}{2}

Rationalize

\frac{1}{2} : \frac{2}{2}

\frac{1}{2}

Multiply by the conjugate

\frac{2}{2}

= \frac{1 \cdot 2}{2 2}

1 \cdot 2 = 2

22 = 2

22

Apply radical rule:

a a = a

22 = 2

= 2

= \frac{2}{2}

= \frac{2}{2}

cos (θ) = \frac{2}{2}

cos (θ) = \frac{2}{2}

cos (θ) = \frac{2}{2}

General solutions for

cos (θ) = \frac{2}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

3 tan (3 x) - 1 = 0, 0 \leq x \leq 2 π

- 2 sin^{2} (x) = 0

x, p + 3 q = 5 z + tan (y - 3 x)

cos (x) = \frac{- 2}{3}

sec (x) = 2, 0 \leq x < 2 π

What is the general solution for 1-sqrt(2)cos(θ)=0 ?
The general solution for 1-sqrt(2)cos(θ)=0 is θ= pi/4+2pin,θ=(7pi)/4+2pin