What is the general solution for 1-sqrt(2)cos(θ)=0 ?

The general solution for 1-sqrt(2)cos(θ)=0 is θ= pi/4+2pin,θ=(7pi)/4+2pin

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1-sqrt(2)cos(θ)=0

1 - 2 cos (θ) = 0

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

1 - 2 cos (θ) = 0

Move

1

to the right side

- 2 cos (θ) = - 1

Divide both sides by

- 2

cos (θ) = \frac{2}{2}

General solutions for

cos (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

3 tan (3 x) - 1 = 0, 0 \leq x \leq 2 π

- 2 sin^{2} (x) = 0

x, p + 3 q = 5 z + tan (y - 3 x)

cos (x) = \frac{- 2}{3}

sec (x) = 2, 0 \leq x < 2 π

What is the general solution for 1-sqrt(2)cos(θ)=0 ?
The general solution for 1-sqrt(2)cos(θ)=0 is θ= pi/4+2pin,θ=(7pi)/4+2pin