What is the general solution for 2sin^2(x)+2sin(x)=0 ?

The general solution for 2sin^2(x)+2sin(x)=0 is x=2pin,x=pi+2pin,x=(3pi)/2+2pin

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2sin^2(x)+2sin(x)=0

2 sin^{2} (x) + 2 sin (x) = 0

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

2 sin^{2} (x) + 2 sin (x) = 0

Solve by substitution

sin (x) = 0, sin (x) = - 1

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{3 π}{2} + 2 πn

2 sin^{2} (x) = sin (x) + 1, 0 \leq x \leq 2 π

15 tan (θ) - 7 = 5 tan (θ) - 3

sin^{2} (x) - 9 cos (x) + 9 = 0, 0 \leq x \leq 2 π

- 10 cos (2 x) - 32 cos (x) - 22 = 0

θ, sin (θ) = - \frac{3}{4}

What is the general solution for 2sin^2(x)+2sin(x)=0 ?
The general solution for 2sin^2(x)+2sin(x)=0 is x=2pin,x=pi+2pin,x=(3pi)/2+2pin