What is the general solution for cos(2x)=(sqrt(2))/2 ,(0,2pi) ?

The general solution for cos(2x)=(sqrt(2))/2 ,(0,2pi) is x= pi/8 ,x=(7pi)/8 ,x=(9pi)/8 ,x=(15pi)/8

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cos(2x)=(sqrt(2))/2 ,(0,2pi)

cos (2 x) = \frac{2}{2}, (0, 2 π)

x = \frac{π}{8}, x = \frac{7 π}{8}, x = \frac{9 π}{8}, x = \frac{15 π}{8}

Solution steps

cos (2 x) = \frac{2}{2}, (0, 2 π)

General solutions for

cos (2 x) = \frac{2}{2}

2 x = \frac{π}{4} + 2 πn, 2 x = \frac{7 π}{4} + 2 πn

Solve

2 x = \frac{π}{4} + 2 πn : x = \frac{π}{8} + πn

Solve

2 x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{8} + πn

x = \frac{π}{8} + πn, x = \frac{7 π}{8} + πn

Solutions for the range

(0, 2 π)

x = \frac{π}{8}, x = \frac{7 π}{8}, x = \frac{9 π}{8}, x = \frac{15 π}{8}

tan (2 x) = 2 tan (x)

- 4 cos (c) - 12 = 2 cos (c) - 6

tan (- 3 x) = 3

sin (A) = \frac{11}{61}

y, x = arctan (y)

What is the general solution for cos(2x)=(sqrt(2))/2 ,(0,2pi) ?
The general solution for cos(2x)=(sqrt(2))/2 ,(0,2pi) is x= pi/8 ,x=(7pi)/8 ,x=(9pi)/8 ,x=(15pi)/8