What is the general solution for 5cos(θ)=-5sin(-θ) ?

The general solution for 5cos(θ)=-5sin(-θ) is θ= pi/4+pin

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5cos(θ)=-5sin(-θ)

5 cos (θ) = - 5 sin (- θ)

θ = \frac{π}{4} + πn

Solution steps

5 cos (θ) = - 5 sin (- θ)

Rewrite using trig identities

5 cos (θ) = 5 sin (θ)

Subtract

5 sin (θ)

from both sides

5 cos (θ) - 5 sin (θ) = 0

Rewrite using trig identities

5 - 5 tan (θ) = 0

Move

5

to the right side

- 5 tan (θ) = - 5

Divide both sides by

- 5

tan (θ) = 1

General solutions for

tan (θ) = 1

θ = \frac{π}{4} + πn

cos (x) - 2 sin (x) cos (x) = 0, 0 \leq x \leq 2 π

sec^{2} (x) + 6 tan (x) = 8

tan (θ) = - \frac{3}{8}

i, arcsin (sin (x)) = x - 2 π

3 cos (2 θ) + 13 cos (θ) + 5 = 6 cos (θ)

What is the general solution for 5cos(θ)=-5sin(-θ) ?
The general solution for 5cos(θ)=-5sin(-θ) is θ= pi/4+pin