What is the general solution for cos^2(θ)=sin^2(θ)+1 ?

The general solution for cos^2(θ)=sin^2(θ)+1 is θ=pin

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cos^2(θ)=sin^2(θ)+1

cos^{2} (θ) = sin^{2} (θ) + 1

θ = πn

Solution steps

cos^{2} (θ) = sin^{2} (θ) + 1

Subtract

sin^{2} (θ) + 1

from both sides

cos^{2} (θ) - sin^{2} (θ) - 1 = 0

Rewrite using trig identities

- 1 + cos (2 θ) = 0

Move

1

to the right side

cos (2 θ) = 1

General solutions for

cos (2 θ) = 1

2 θ = 0 + 2 πn

Solve

2 θ = 0 + 2 πn : θ = πn

θ = πn

sin (x + \frac{π}{4}) + sin (x - \frac{π}{4}) - 1 = 0

\frac{1}{2} sin (x) = - \frac{3}{4}

cos^{2} (x) + 3 cos (x) - 4 = 0

7 sin (x) = cos (x) - 3

sin (a) = \frac{3}{4}

What is the general solution for cos^2(θ)=sin^2(θ)+1 ?
The general solution for cos^2(θ)=sin^2(θ)+1 is θ=pin