What is the general solution for cos(3x)=0,0<x<pi ?

The general solution for cos(3x)=0,0<x<pi is x= pi/6 ,x= pi/2 ,x=(5pi)/6

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cos(3x)=0,0<x<pi

cos (3 x) = 0, 0 < x < π

x = \frac{π}{6}, x = \frac{π}{2}, x = \frac{5 π}{6}

Solution steps

cos (3 x) = 0, 0 < x < π

General solutions for

cos (3 x) = 0

3 x = \frac{π}{2} + 2 πn, 3 x = \frac{3 π}{2} + 2 πn

Solve

3 x = \frac{π}{2} + 2 πn : x = \frac{π}{6} + \frac{2 πn}{3}

Solve

3 x = \frac{3 π}{2} + 2 πn : x = \frac{π}{2} + \frac{2 πn}{3}

x = \frac{π}{6} + \frac{2 πn}{3}, x = \frac{π}{2} + \frac{2 πn}{3}

Solutions for the range

0 < x < π

x = \frac{π}{6}, x = \frac{π}{2}, x = \frac{5 π}{6}

12 csc (x) = 3 csc (x) + 63

2 - 2 csc^{2} (x) = - csc^{2} (x) + csc (x)

2 sin (x) + sin (2 x) + cos (x) = - 1

4 cot (x) + 5 = 1

\frac{1}{36} + cos^{2} (θ) = 1

What is the general solution for cos(3x)=0,0<x<pi ?
The general solution for cos(3x)=0,0<x<pi is x= pi/6 ,x= pi/2 ,x=(5pi)/6