What is the general solution for 4sin(x-pi)+2=0 ?

The general solution for 4sin(x-pi)+2=0 is x=(7pi)/6+2pin+pi,x=(11pi)/6+2pin+pi

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4sin(x-pi)+2=0

4 sin (x - π) + 2 = 0

x = \frac{7 π}{6} + 2 πn + π, x = \frac{11 π}{6} + 2 πn + π

Solution steps

4 sin (x - π) + 2 = 0

Move

2

to the right side

4 sin (x - π) = - 2

Divide both sides by

4

sin (x - π) = - \frac{1}{2}

General solutions for

sin (x - π) = - \frac{1}{2}

x - π = \frac{7 π}{6} + 2 πn, x - π = \frac{11 π}{6} + 2 πn

Solve

x - π = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{6} + 2 πn + π

Solve

x - π = \frac{11 π}{6} + 2 πn : x = \frac{11 π}{6} + 2 πn + π

x = \frac{7 π}{6} + 2 πn + π, x = \frac{11 π}{6} + 2 πn + π

\frac{1}{2} tan (2 x) = tan (x)

sin (x + π) + cos (x + π) = 0

2 sin^{2} (x) - 3 sin (x) = - 1, 0 \leq x \leq 2 π

5 cos (x) + 23 = cos (x)

cos^{2} (x) + 2 sin (x) - 2 = 0

What is the general solution for 4sin(x-pi)+2=0 ?
The general solution for 4sin(x-pi)+2=0 is x=(7pi)/6+2pin+pi,x=(11pi)/6+2pin+pi