What is the general solution for tan^2(θ)=sqrt(3)tan(θ) ?

The general solution for tan^2(θ)=sqrt(3)tan(θ) is θ= pi/3+pin,θ=pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tan^2(θ)=sqrt(3)tan(θ)

tan^{2} (θ) = 3 tan (θ)

θ = \frac{π}{3} + πn, θ = πn

Solution steps

tan^{2} (θ) = 3 tan (θ)

Solve by substitution

tan (θ) = 3, tan (θ) = 0

tan (θ) = 3 : θ = \frac{π}{3} + πn

tan (θ) = 0 : θ = πn

Combine all the solutions

θ = \frac{π}{3} + πn, θ = πn

4 sin^{2} (2) cot (x) - 2 = 0

5 sin (2 θ) + 2 sin (θ) = 0

cos^{2} (x) = \frac{19}{20}

sin (x) = \frac{1000}{2022}

x, arcsin (x) = ln (y)

What is the general solution for tan^2(θ)=sqrt(3)tan(θ) ?
The general solution for tan^2(θ)=sqrt(3)tan(θ) is θ= pi/3+pin,θ=pin