What is the general solution for cos(5x)=-1,0<= x<2pi ?

The general solution for cos(5x)=-1,0<= x<2pi is x= pi/5 ,x=(3pi)/5 ,x=pi,x=(7pi)/5 ,x=(9pi)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

cos(5x)=-1,0<= x<2pi

cos (5 x) = - 1, 0 \leq x < 2 π

x = \frac{π}{5}, x = \frac{3 π}{5}, x = π, x = \frac{7 π}{5}, x = \frac{9 π}{5}

Solution steps

cos (5 x) = - 1, 0 \leq x < 2 π

General solutions for

cos (5 x) = - 1

5 x = π + 2 πn

Solve

5 x = π + 2 πn : x = \frac{π}{5} + \frac{2 πn}{5}

x = \frac{π}{5} + \frac{2 πn}{5}

Solutions for the range

0 \leq x < 2 π

x = \frac{π}{5}, x = \frac{3 π}{5}, x = π, x = \frac{7 π}{5}, x = \frac{9 π}{5}

sinh (x) = - 1

3 cos^{2} (x) + 2 sin (x) - 3 = 0

cot (x) = - 2

cos (c) = \frac{15}{17}

sin (θ) = 0.3907

What is the general solution for cos(5x)=-1,0<= x<2pi ?
The general solution for cos(5x)=-1,0<= x<2pi is x= pi/5 ,x=(3pi)/5 ,x=pi,x=(7pi)/5 ,x=(9pi)/5