What is the value of arccos(sin((5pi)/6)) ?

The value of arccos(sin((5pi)/6)) is pi/3

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arccos(sin((5pi)/6))

arccos (sin (\frac{5 π}{6}))

\frac{π}{3}

Solution steps

arccos (sin (\frac{5 π}{6}))

Rewrite using trig identities:

sin (\frac{5 π}{6}) = sin (\frac{π}{6})

= arccos (sin (\frac{π}{6}))

Rewrite using trig identities:

sin (\frac{π}{6}) = cos (\frac{π}{3})

= arccos (cos (\frac{π}{3}))

Use the inverse trig property:

\frac{π}{3}

= \frac{π}{3}

tan (5 7^{\circ})

sin (6 8^{\circ})

cos (0 π)

30 sin (3 0^{\circ})

cos (\frac{4}{3} π)

What is the value of arccos(sin((5pi)/6)) ?
The value of arccos(sin((5pi)/6)) is pi/3