What is the general solution for 0=2sin(2x) ?

The general solution for 0=2sin(2x) is x=pin,x= pi/2+pin

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0=2sin(2x)

0 = 2 sin (2 x)

x = πn, x = \frac{π}{2} + πn

Solution steps

0 = 2 sin (2 x)

Switch sides

2 sin (2 x) = 0

Divide both sides by

2

sin (2 x) = 0

General solutions for

sin (2 x) = 0

2 x = 0 + 2 πn, 2 x = π + 2 πn

Solve

2 x = 0 + 2 πn : x = πn

Solve

2 x = π + 2 πn : x = \frac{π}{2} + πn

x = πn, x = \frac{π}{2} + πn

sec^{2} (x) = tan (x) + 1

x, cos (x) - sin (2 x) = 0

- \frac{2}{3} cos (3 θ) = 1, 0 \leq θ \leq 2 π

8 (cos (x))^{2} - 6 sin (x) = 3

sin (x) = \frac{- tan ( x )}{2}

What is the general solution for 0=2sin(2x) ?
The general solution for 0=2sin(2x) is x=pin,x= pi/2+pin