What is the general solution for solvefor x,1+sin(2x)=0 ?

The general solution for solvefor x,1+sin(2x)=0 is x=(3pi)/4+pin

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solvefor x,1+sin(2x)=0

solve for

x, 1 + sin (2 x) = 0

x = \frac{3 π}{4} + πn

Solution steps

1 + sin (2 x) = 0

Move

1

to the right side

sin (2 x) = - 1

General solutions for

sin (2 x) = - 1

2 x = \frac{3 π}{2} + 2 πn

Solve

2 x = \frac{3 π}{2} + 2 πn : x = \frac{3 π}{4} + πn

x = \frac{3 π}{4} + πn

- cos (θ) + 2 cos^{2} (θ) = 0

sin (x) = 2 sin (x) + 1

4 cosh (x) - sinh (x) = 8

- 53 cot (θ) + 1 = 16

- sin (x) = sin (x)

What is the general solution for solvefor x,1+sin(2x)=0 ?
The general solution for solvefor x,1+sin(2x)=0 is x=(3pi)/4+pin