What is the general solution for solvefor t,x=5cos(t) ?

The general solution for solvefor t,x=5cos(t) is t=arccos(x/5)+2pin,t=-arccos(x/5)+2pin

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solvefor t,x=5cos(t)

solve for

t, x = 5 cos (t)

t = arccos (\frac{x}{5}) + 2 πn, t = - arccos (\frac{x}{5}) + 2 πn

Solution steps

x = 5 cos (t)

Switch sides

5 cos (t) = x

Divide both sides by

5

cos (t) = \frac{x}{5}

Apply trig inverse properties

t = arccos (\frac{x}{5}) + 2 πn, t = - arccos (\frac{x}{5}) + 2 πn

tan (θ) = \frac{π}{2}

49 sin (2 β) = 25, tan (β) < 0

cos (θ) = - 0.076

4 cos^{2} (θ) = 2, 0 \leq θ \leq 2 π

sin (θ) = \frac{21}{29}

What is the general solution for solvefor t,x=5cos(t) ?
The general solution for solvefor t,x=5cos(t) is t=arccos(x/5)+2pin,t=-arccos(x/5)+2pin