What is the general solution for 4tan^2(θ)+5tan(θ)=6 ?

The general solution for 4tan^2(θ)+5tan(θ)=6 is θ=0.64350…+pin,θ=-1.10714…+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4tan^2(θ)+5tan(θ)=6

4 tan^{2} (θ) + 5 tan (θ) = 6

θ = 0.64350 \dots + πn, θ = - 1.10714 \dots + πn

Solution steps

4 tan^{2} (θ) + 5 tan (θ) = 6

Solve by substitution

tan (θ) = \frac{3}{4}, tan (θ) = - 2

tan (θ) = \frac{3}{4} : θ = arctan (\frac{3}{4}) + πn

tan (θ) = - 2 : θ = arctan (- 2) + πn

Combine all the solutions

θ = arctan (\frac{3}{4}) + πn, θ = arctan (- 2) + πn

Show solutions in decimal form

θ = 0.64350 \dots + πn, θ = - 1.10714 \dots + πn

sin (t) = cos (t)

- 2 sin^{2} (3 x) = 3 cos (3 x)

2 cot (x) + csc (x) = 0

sin (x) = - 0.15

74 = 58 cos (x) + 71 sin (x)

What is the general solution for 4tan^2(θ)+5tan(θ)=6 ?
The general solution for 4tan^2(θ)+5tan(θ)=6 is θ=0.64350…+pin,θ=-1.10714…+pin