What is the general solution for sin(1/x)=-1 ?

The general solution for sin(1/x)=-1 is x= 2/(pi(3+4n));\quad n\ne-3/4

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sin(1/x)=-1

sin (\frac{1}{x}) = - 1

x = \frac{2}{π ( 3 + 4 n )}; n \neq = - \frac{3}{4}

Solution steps

sin (\frac{1}{x}) = - 1

General solutions for

sin (\frac{1}{x}) = - 1

\frac{1}{x} = \frac{3 π}{2} + 2 πn

Solve

\frac{1}{x} = \frac{3 π}{2} + 2 πn : x = \frac{2}{π ( 3 + 4 n )}; n \neq = - \frac{3}{4}

x = \frac{2}{π ( 3 + 4 n )}; n \neq = - \frac{3}{4}

5 sin (x) + 4 = 0

cos^{2} (\frac{x}{2}) = 0

tan (θ) = - \frac{7}{24}

2 sin (2 θ) = - 3

- 4 cot^{2} (x) = 1 + 2 cot (x) - 3 cot^{2} (x)

What is the general solution for sin(1/x)=-1 ?
The general solution for sin(1/x)=-1 is x= 2/(pi(3+4n));\quad n\ne-3/4