What is the general solution for sin(θ)=-0.8 ?

The general solution for sin(θ)=-0.8 is θ=-0.92729…+2pin,θ=pi+0.92729…+2pin

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sin(θ)=-0.8

sin (θ) = - 0.8

θ = - 0.92729 \dots + 2 πn, θ = π + 0.92729 \dots + 2 πn

Solution steps

sin (θ) = - 0.8

Apply trig inverse properties

θ = arcsin (- 0.8) + 2 πn, θ = π + arcsin (0.8) + 2 πn

Show solutions in decimal form

θ = - 0.92729 \dots + 2 πn, θ = π + 0.92729 \dots + 2 πn

cos (x^{2}) + sin (x^{2}) = 1

cos (\frac{x}{3} - \frac{π}{4}) = \frac{1}{2}

12 sin^{2} (x) + 7 cos (x) - 13 = 0

tan (3 x - π) = 1

sin (2 x) cos (x) + cos (2 x) sin (x) = 1

What is the general solution for sin(θ)=-0.8 ?
The general solution for sin(θ)=-0.8 is θ=-0.92729…+2pin,θ=pi+0.92729…+2pin