What is the general solution for 2cos(θ)=sqrt(2),0<= θ<2pi ?

The general solution for 2cos(θ)=sqrt(2),0<= θ<2pi is θ= pi/4 ,θ=(7pi)/4

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2cos(θ)=sqrt(2),0<= θ<2pi

2 cos (θ) = 2, 0 \leq θ < 2 π

θ = \frac{π}{4}, θ = \frac{7 π}{4}

Solution steps

2 cos (θ) = 2, 0 \leq θ < 2 π

Divide both sides by

2

cos (θ) = \frac{2}{2}

General solutions for

cos (θ) = \frac{2}{2}

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solutions for the range

0 \leq θ < 2 π

θ = \frac{π}{4}, θ = \frac{7 π}{4}

cosh (θ) = 4 - j

\frac{1}{2} = tan (x)

7 sec (θ) = - 9.2

cos (x) = \frac{3 3}{2 π}

\frac{sin ( b )}{19} = \frac{sin ( 7 4 ^{\circ} )}{19}

What is the general solution for 2cos(θ)=sqrt(2),0<= θ<2pi ?
The general solution for 2cos(θ)=sqrt(2),0<= θ<2pi is θ= pi/4 ,θ=(7pi)/4