What is the general solution for 2sin(2x+10)-sqrt(3)=0 ?

The general solution for 2sin(2x+10)-sqrt(3)=0 is x=-5+pin+pi/6 ,x=-5+pin+pi/3

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2sin(2x+10)-sqrt(3)=0

2 sin (2 x + 10) - 3 = 0

x = - 5 + πn + \frac{π}{6}, x = - 5 + πn + \frac{π}{3}

Solution steps

2 sin (2 x + 10) - 3 = 0

Move

3

to the right side

2 sin (2 x + 10) = 3

Divide both sides by

2

sin (2 x + 10) = \frac{3}{2}

General solutions for

sin (2 x + 10) = \frac{3}{2}

2 x + 10 = \frac{π}{3} + 2 πn, 2 x + 10 = \frac{2 π}{3} + 2 πn

Solve

2 x + 10 = \frac{π}{3} + 2 πn : x = - 5 + πn + \frac{π}{6}

Solve

2 x + 10 = \frac{2 π}{3} + 2 πn : x = - 5 + πn + \frac{π}{3}

x = - 5 + πn + \frac{π}{6}, x = - 5 + πn + \frac{π}{3}

cos (θ) = \frac{13}{6 \cdot 86}

\frac{1 + tan ( x )}{1 + cot ( x )} = 2

tan (x) + 1 = \frac{1}{3} + \frac{1}{3} cot (x)

sin (8 x) = 1

2 cos^{2} (w) - 3 cos (w) - 5 = 0

What is the general solution for 2sin(2x+10)-sqrt(3)=0 ?
The general solution for 2sin(2x+10)-sqrt(3)=0 is x=-5+pin+pi/6 ,x=-5+pin+pi/3