What is the general solution for 2sin(3x)cos(3x)=1 ?

The general solution for 2sin(3x)cos(3x)=1 is x= pi/(12)+(pin)/3

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2sin(3x)cos(3x)=1

2 sin (3 x) cos (3 x) = 1

x = \frac{π}{12} + \frac{πn}{3}

Solution steps

2 sin (3 x) cos (3 x) = 1

Rewrite using trig identities

sin (2 \cdot 3 x) = 1

General solutions for

sin (2 \cdot 3 x) = 1

2 \cdot 3 x = \frac{π}{2} + 2 πn

Solve

2 \cdot 3 x = \frac{π}{2} + 2 πn : x = \frac{π}{12} + \frac{πn}{3}

x = \frac{π}{12} + \frac{πn}{3}

sin (x) = \frac{3 10}{10}

cos (θ) = 2

6 sin (x) + 15 = 15

sin (x) = 1 + cos^{2} (x)

cos^{2} (x) + 4 cos (x) + 1 = 0

What is the general solution for 2sin(3x)cos(3x)=1 ?
The general solution for 2sin(3x)cos(3x)=1 is x= pi/(12)+(pin)/3