What is the general solution for 2=3+2sin(θ) ?

The general solution for 2=3+2sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

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2=3+2sin(θ)

2 = 3 + 2 sin (θ)

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

2 = 3 + 2 sin (θ)

Switch sides

3 + 2 sin (θ) = 2

Move

3

to the right side

2 sin (θ) = - 1

Divide both sides by

2

sin (θ) = - \frac{1}{2}

General solutions for

sin (θ) = - \frac{1}{2}

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

- 2 sin (θ) + sin (2 θ) = 0

- 2 sin^{2} (x) - 3 sin (x) + 2 = 0

tan (β) = \frac{1}{2}

cos (B) = \frac{4}{5}

2 sin^{2} (x) - 3 cos (2 x) = 3

What is the general solution for 2=3+2sin(θ) ?
The general solution for 2=3+2sin(θ) is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin