What is the general solution for sec(a)= 41/12 ,2pi<a<(5pi)/2 ,sin(a/2) ?

The general solution for sec(a)= 41/12 ,2pi<a<(5pi)/2 ,sin(a/2) is a=1.27376…+2pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sec(a)= 41/12 ,2pi<a<(5pi)/2 ,sin(a/2)

sec (a) = \frac{41}{12}, 2 π < a < \frac{5 π}{2}, sin (\frac{a}{2})

a = 1.27376 \dots + 2 π

Solution steps

sec (a) = \frac{41}{12}, 2 π < a < \frac{5 π}{2}, sin (\frac{a}{2})

Apply trig inverse properties

a = arcsec (\frac{41}{12}) + 2 πn, a = 2 π - arcsec (\frac{41}{12}) + 2 πn

Solutions for the range

2 π < a < \frac{5 π}{2}

a = arcsec (\frac{41}{12}) + 2 π

Show solutions in decimal form

a = 1.27376 \dots + 2 π

sin (2 x) = 0.3

sin (2 x) = 0.6

- 2 cos (t) = 0

4 cos^{2} (θ) - 4 cos (θ) - 3 = 0

4 sin (x) + 3 cos (x) = 2

What is the general solution for sec(a)= 41/12 ,2pi<a<(5pi)/2 ,sin(a/2) ?
The general solution for sec(a)= 41/12 ,2pi<a<(5pi)/2 ,sin(a/2) is a=1.27376…+2pi