What is the general solution for 6sin^2(θ)-10sin(θ)-8=-3sin(θ)-3 ?

The general solution for 6sin^2(θ)-10sin(θ)-8=-3sin(θ)-3 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6sin^2(θ)-10sin(θ)-8=-3sin(θ)-3

6 sin^{2} (θ) - 10 sin (θ) - 8 = - 3 sin (θ) - 3

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Solution steps

6 sin^{2} (θ) - 10 sin (θ) - 8 = - 3 sin (θ) - 3

Solve by substitution

sin (θ) = \frac{5}{3}, sin (θ) = - \frac{1}{2}

sin (θ) = \frac{5}{3} :

No Solution

sin (θ) = - \frac{1}{2} : θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Combine all the solutions

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

sin (4 θ) - sin (6 θ) = 0

sin (x) = \frac{3}{10}

9 csc^{2} (x) + 7 = 19

sin^{2} (x) = \frac{1}{2} + \frac{1}{2} cos (2 x)

tan (x) = \frac{8}{12}

What is the general solution for 6sin^2(θ)-10sin(θ)-8=-3sin(θ)-3 ?
The general solution for 6sin^2(θ)-10sin(θ)-8=-3sin(θ)-3 is θ=(7pi)/6+2pin,θ=(11pi)/6+2pin