What is the general solution for sin(θ)=(150sin(115))/(212.6) ?

The general solution for sin(θ)=(150sin(115))/(212.6) is θ=0.69377…+360n,θ=180-0.69377…+360n

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sin(θ)=(150sin(115))/(212.6)

sin (θ) = \frac{150 sin ( 11 5 ^{\circ} )}{212.6}

θ = 0.69377 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.69377 \dots + 36 0^{\circ} n

Solution steps

sin (θ) = \frac{150 sin ( 11 5 ^{\circ} )}{212.6}

Apply trig inverse properties

θ = arcsin (\frac{150 sin ( 11 5 ^{\circ} )}{212.6}) + 36 0^{\circ} n, θ = 18 0^{\circ} - arcsin (\frac{150 sin ( 11 5 ^{\circ} )}{212.6}) + 36 0^{\circ} n

Show solutions in decimal form

θ = 0.69377 \dots + 36 0^{\circ} n, θ = 18 0^{\circ} - 0.69377 \dots + 36 0^{\circ} n

- sin (x) - sin (2 x) = 0

2 cos^{2} (2 x) + cos (2 x) - 1 = 0

cos (θ) = \frac{0}{8}

3 sin (x) + 2 = 1

sin (y) = - 1

What is the general solution for sin(θ)=(150sin(115))/(212.6) ?
The general solution for sin(θ)=(150sin(115))/(212.6) is θ=0.69377…+360n,θ=180-0.69377…+360n