What is the general solution for tan(x/4)=-sqrt(3) ?

The general solution for tan(x/4)=-sqrt(3) is x=(8pi)/3+4pin

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tan(x/4)=-sqrt(3)

tan (\frac{x}{4}) = - 3

x = \frac{8 π}{3} + 4 πn

Degrees

x = 48 0^{\circ} + 72 0^{\circ} n

Solution steps

tan (\frac{x}{4}) = - 3

General solutions for

tan (\frac{x}{4}) = - 3

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

\frac{x}{4} = \frac{2 π}{3} + πn

\frac{x}{4} = \frac{2 π}{3} + πn

Solve

\frac{x}{4} = \frac{2 π}{3} + πn : x = \frac{8 π}{3} + 4 πn

\frac{x}{4} = \frac{2 π}{3} + πn

Multiply both sides by

4

\frac{x}{4} = \frac{2 π}{3} + πn

Multiply both sides by

4

\frac{4 x}{4} = 4 \cdot \frac{2 π}{3} + 4 πn

Simplify

\frac{4 x}{4} = 4 \cdot \frac{2 π}{3} + 4 πn

Simplify

\frac{4 x}{4} : x

\frac{4 x}{4}

Divide the numbers:

\frac{4}{4} = 1

= x

Simplify

4 \cdot \frac{2 π}{3} + 4 πn : \frac{8 π}{3} + 4 πn

4 \cdot \frac{2 π}{3} + 4 πn

4 \cdot \frac{2 π}{3} = \frac{8 π}{3}

4 \cdot \frac{2 π}{3}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 π 4}{3}

Multiply the numbers:

2 \cdot 4 = 8

= \frac{8 π}{3}

= \frac{8 π}{3} + 4 πn

x = \frac{8 π}{3} + 4 πn

x = \frac{8 π}{3} + 4 πn

x = \frac{8 π}{3} + 4 πn

x = \frac{8 π}{3} + 4 πn

8 sin^{2} (x) - 2 sin (x) - 1 = 0, - \frac{π}{2} < x < \frac{π}{2}

cos (4 x) - cos (3 x) = 0

2 cos^{2} (A) + cos (A) - 1 = 0

tan^{3} (x) = tan (x), 0 \leq x \leq 2 π

sin (x^{2} + 3 x + 5) = 0

What is the general solution for tan(x/4)=-sqrt(3) ?
The general solution for tan(x/4)=-sqrt(3) is x=(8pi)/3+4pin