What is the general solution for 4cos(2x)=2sqrt(2) ?

The general solution for 4cos(2x)=2sqrt(2) is x= pi/8+pin,x=(7pi)/8+pin

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4cos(2x)=2sqrt(2)

4 cos (2 x) = 22

x = \frac{π}{8} + πn, x = \frac{7 π}{8} + πn

Solution steps

4 cos (2 x) = 22

Divide both sides by

4

cos (2 x) = \frac{2}{2}

General solutions for

cos (2 x) = \frac{2}{2}

2 x = \frac{π}{4} + 2 πn, 2 x = \frac{7 π}{4} + 2 πn

Solve

2 x = \frac{π}{4} + 2 πn : x = \frac{π}{8} + πn

Solve

2 x = \frac{7 π}{4} + 2 πn : x = \frac{7 π}{8} + πn

x = \frac{π}{8} + πn, x = \frac{7 π}{8} + πn

4 sin^{4} (x) - 13 sin^{2} (x) + 3 = 0

3 tan (\frac{2 x}{3}) - 1 = 0

8 cos^{2} (θ) - 3 = 1

1 + 2 sin (x) = csc (x)

tan^{2} (θ) + tan (θ) - 6 = 0

What is the general solution for 4cos(2x)=2sqrt(2) ?
The general solution for 4cos(2x)=2sqrt(2) is x= pi/8+pin,x=(7pi)/8+pin