What is the general solution for sin(θ)=-(sqrt(68))/9 ?

The general solution for sin(θ)=-(sqrt(68))/9 is θ=-1.15860…+2pin,θ=pi+1.15860…+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(θ)=-(sqrt(68))/9

sin (θ) = - \frac{68}{9}

θ = - 1.15860 \dots + 2 πn, θ = π + 1.15860 \dots + 2 πn

Solution steps

sin (θ) = - \frac{68}{9}

68 = 217

sin (θ) = - \frac{2 17}{9}

Apply trig inverse properties

θ = arcsin (- \frac{2 17}{9}) + 2 πn, θ = π + arcsin (\frac{2 17}{9}) + 2 πn

Show solutions in decimal form

θ = - 1.15860 \dots + 2 πn, θ = π + 1.15860 \dots + 2 πn

sec (θ) = 6

tan (2 x - \frac{π}{3}) = - 3

3 sin^{2} (2 θ) + 8 cos (2 θ) = 0

cos (2 x - \frac{π}{3}) = \frac{1}{2}

sin (θ) = \frac{7}{11}

What is the general solution for sin(θ)=-(sqrt(68))/9 ?
The general solution for sin(θ)=-(sqrt(68))/9 is θ=-1.15860…+2pin,θ=pi+1.15860…+2pin